pyDes库 实现python的des加密,注册机

pyDes库 实现python的des加密,注册机
QQ群：397745473

下载及简介地址：https://twhiteman.netfirms.com/des.html

如需要在python中使用des加密，可以直接使用pyDes库加密，该库提供了CBC和ECB两种加密方式。

1、Windows下安装

　　下载后pyDes-x.x.x.zip并解压后，里面有setup.py文件，使用命令 setup.py –help可查看详细使用。

　　你可以使用命令 python setup.py install 命令安装，也可以直接将压缩包内的pyDes.py拷贝到本地的python lib库下直接开始使用

2、 使用

　　使用参数如下（拷贝自上述提供的地址）：

Class initialization
--------------------
pyDes.des(key, [mode], [IV], [pad], [padmode])
pyDes.triple_des(key, [mode], [IV], [pad], [padmode])

key     -> Bytes containing the encryption key. 8 bytes for DES, 16 or 24 bytes
	   for Triple DES
mode    -> Optional argument for encryption type, can be either
	   pyDes.ECB (Electronic Code Book) or pyDes.CBC (Cypher Block Chaining)
IV      -> Optional Initial Value bytes, must be supplied if using CBC mode.
	   Length must be 8 bytes.
pad     -> Optional argument, set the pad character (PAD_NORMAL) to use during
	   all encrypt/decrpt operations done with this instance.
padmode -> Optional argument, set the padding mode (PAD_NORMAL or PAD_PKCS5)
	   to use during all encrypt/decrpt operations done with this instance.

I recommend to use PAD_PKCS5 padding, as then you never need to worry about any
padding issues, as the padding can be removed unambiguously upon decrypting
data that was encrypted using PAD_PKCS5 padmode.

Common methods
--------------
encrypt(data, [pad], [padmode])
decrypt(data, [pad], [padmode])

data    -> Bytes to be encrypted/decrypted
pad     -> Optional argument. Only when using padmode of PAD_NORMAL. For
	   encryption, adds this characters to the end of the data block when
	   data is not a multiple of 8 bytes. For decryption, will remove the
	   trailing characters that match this pad character from the last 8
	   bytes of the unencrypted data block.
padmode -> Optional argument, set the padding mode, must be one of PAD_NORMAL
	   or PAD_PKCS5). Defaults to PAD_NORMAL

使用实例:

Example
-------
from pyDes import *

# For Python3, you‘ll need to use bytes, i.e.:
#   data = b"Please encrypt my data"
#   k = des(b"DESCRYPT", CBC, b"\0\0\0\0\0\0\0\0", pad=None, padmode=PAD_PKCS5)

data = "Please encrypt my data"
k = des("DESCRYPT", CBC, "\0\0\0\0\0\0\0\0", pad=None, padmode=PAD_PKCS5)
d = k.encrypt(data)
print "Encrypted: %r" % d
print "Decrypted: %r" % k.decrypt(d)
assert k.decrypt(d, padmode=PAD_PKCS5) == dat

以下是本人使用的例子,使用CBC加密的方式：

import base64
from pyDes import *

Des_Key = "BHC#@*UM" # Key
Des_IV = "\x22\x33\x35\x81\xBC\x38\x5A\xE7" # 自定IV向量

def DesEncrypt(str):
    k = des(Des_Key, CBC, Des_IV, pad=None, padmode=PAD_PKCS5)

    EncryptStr = k.encrypt(str)

    return base64.b64encode(EncryptStr) #转base64编码返回
	

Python DES 加密解密，就是大家所谓想要的那个非常快速的方法
这个要借助Crypto.Cipher这个插件来实现的，引用后只需要写如下代码即可

from Crypto.Cipher import DES

class MyDESCrypt:
    
    key = chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)
    iv = chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)
    
    def __init__(self,key='',iv=''):
        if len(key)> 0:
            self.key = key
        if len(iv)>0 :
            self.iv = iv
        
    def ecrypt(self,ecryptText):
       try:
           cipherX = DES.new(self.key, DES.MODE_CBC, self.iv)
           pad = 8 - len(ecryptText) % 8
           padStr = ""
           for i in range(pad):
              padStr = padStr + chr(pad)
           ecryptText = ecryptText + padStr
           x = cipherX.encrypt(ecryptText)
           return x.encode('hex_codec').upper()
       except:
           return ""
      
   
    def decrypt(self,decryptText):
        try:
            
            cipherX = DES.new(self.key, DES.MODE_CBC, self.iv)
            str = decryptText.decode('hex_codec')
            y = cipherX.decrypt(str)
            return y[0:ord(y[len(y)-1])*-1]
        except:
            return ""

QQ群：397745473